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240-pin DDR3 DIMMs DDR3 RAM sticks are physically the same size as the 184-pin DDR DIMMs, but the guide notch is in a different location DDR3 uses a 240-pin DIMM (see Figure 6-8) that s not compatible with DDR RAM slots or motherboards DDR3 has a triple-channel architecture and performs faster at higher frequencies but at lower voltages, thus generating less heat The laptop version of DDR3 is a 204-pin SO-DIMM

Once we finish writing the linked list into the file, we ll close the file by calling fclose():

fclose( fp ); } ReadFile() starts by opening the file dvdData for reading. If we can t open the file, we ll

=(i-g (g,N)

DDR3 DIMMs are not backward compatible inserting a DDR3 module into a DDR2 socket can damage the DIMM and/or the motherboard

print an error message and return, leaving the list empty:

/****************************> ReadFile <*/ void ReadFile( void ) { FILE *fp; struct DVDInfo *infoPtr; if ( ( fp = fopen( kDVDFileName, "r" ) ) == NULL ) { printf( "***ERROR: Could not read DVD file!" ); return; }

Step 2 In your PC or motherboard documentation, or on the manufacturer s Web site, locate the section listing the type of RAM your system uses What speed of RAM does your system need __________________________ Step 3 Using the disassembled PC at your workspace, locate the motherboard and the anti-static bag containing the RAM sticks, and make note of the following: How many RAM slots does your motherboard have ________________________ How many RAM slots are lled with RAM sticks __________________________ Can you tell at a glance whether your system has DIMMs, RIMMs, DDR DIMMs, DDR2 DIMMs, or DDR3 DIMMs ________________________

With the file open, we ll enter a loop that continues as long as ReadStructFromFile() returns true. By using the do-while loop, we ll execute the body of the loop before we call ReadStructFromFile() for the first time. This is what we want. The body of the loop attempts to allocate a block of memory the size of a DVDInfo struct. If the malloc() fails, we ll bail out of the program.

do { infoPtr = malloc( sizeof( struct DVDInfo ) ); if ( NULL == infoPtr ) { printf( "Out of memory!!! exit( 0 ); }

Note that g, the fraction of time~when the pipeline is full, is analogous t o / , the vectorizability of the program in the parallel processor model Therefore, Amdahl's law can be analogously applied to pipelined processors As g drops off just slightly from 100%, the speedup or the performance of a pipelined processor can drop off very quickly In other words, the actual performance gain that can be obtained through pipelining can be strongly degraded by just a small fraction of stall cycles As the degree of pipelining N increases, the traction of stall cycles will become increasjngjy_dpvasfa speedup that can te_achieyed by a pipeline processor Stall cycles in pipelined processors are now the key adversary aricTare analogous to the sequential bottleneck for parallel processors Essentially, stall cycles constitute the pipelined processor's sequential bottleneck Equation (15) is a simple performance model for pipelined processors based on Amdahl's law for parallel processors It is assumed in this model that whenever the pipeline is stalled, there is only one instruction in the pipeline, or it effectively becomes a sequential nonpipelined processor The implication is that when a pipeline is stalled no overlapping of instructions is allowed; this is effectively equivalent to stalling the pipeline for N cycles to allow the instruction causing the stall to completely traverse the pipelifieTWe know, however, that with clever design of the pipeline, such as with the use of forwarding paths, to resolve a hazard that causes a pipeline stall, the number of penalty cycles incurred is not necessarily N and most likely less than N Based on this observation, a refinement to the model of Equation (15) is possible 5=

Goodbye!\n" );