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Pipelining is a very effective means of improving processor performance, and there are strong motivations for employing deep pipelines A deeper pipeline increases the number of pipeline stages and reduces the number of logic gate levels in each pipeline stage The primary benefit of deeper pipelines is the ability to reduce the machine cycle time and hence increase the clocking frequency During the 1980s most pipelined microprocessors had four to six pipeline stages Contemporary high-end microprocessors have clocking frequencies in the multiple-gigahertz range, and pipeline depths have increased to more than 20 pipeline stages Pipelines have gotten not only deeper, but also wider, such as superscalar processors As pipelines get wider, there is increased complexity in each pipeline stage, which can increase the delay of each pipeline stage To maintain the same clocking frequency, a wider pipeline will need to be made even deeper There is a downside to deeper pipelines With a deeper pipeline the penalties incurred for pipeline hazard resolution can become larger Figure 223 illustrates what can happen to the ALU, load, and branch penalties when a pipeline becomes wider and much deeper Comparing the shallow and the deep pipelines, we see that the ALU penalty increases from zero cycles to one cycle, the load penalty increases from one cycle to four cycles, and most importandy, the branch penalty goes from three cycles to eleven cycles With increased pipeline penalties, the average CPI increases The potential performance gain due to the higher clocking frequency of a deeper pipeline can be ameliorated by the increase of CPI To ensure overall performance improvement with a deeper pipeline, the increase in clocking frequency must exceed the increase in CPI There are two approaches that can be used to mitigate the negative impact of the increased branch penalty in deep pipelines; see Figure 224 Among the three pipeline penalties, the branch penalty is the most severe because it spans all the front-end pipeline stages With a mispredicted branch, all the instructions in the front-end pipeline stages must be flushed The first approach to reduce the branch.

The materials you need for this lab are A working computer system with a oppy drive installed A known good oppy disk with data

8

1. What s wrong with each of the following code fragments a. If the char type defaults to signed (very likely), c can hold only values from 128 to 127. Even if your char does default to unsigned, this code is dangerous. At the very least, use an unsigned char. Even better, use a short, int, or long. b. Use %f, %g, or %e to print the value of a float, not %d. Also, the variable being printed is f. It should be myFloat. c. The text string "a" is composed of two characters, both 'a' and the terminating zero byte. The variable c is only a single byte in size. Even if c were 2 bytes long, you couldn t copy a text string this way. Try copying the text one byte at a time into a variable large enough to hold the text string and its terminating zero byte. d. Once again, this code uses the wrong approach to copying a text string, and once again, not enough memory is allocated to hold the text string and its zero byte. e. The #define of kMaxArraySize must come before the first non-#define reference to it. f. This definition

Although this lab starts with a working oppy drive installed in a PC a likely scenario in a classroom setting you would obviously need to install one yourself when building a system On a new system (or if you are reassembling the disassembled, non-production machine from 3), you d start this lab at Step 5

char c[ kMaxArraySize ];

creates an array ranging from c[0] to c[kMaxArraySize-1]. The reference to c[kMaxArraySize] is out of bounds. g. The problem occurs in the line:

- Decode\ "Dispatch"

Step 1 Begin with the PC turned on and the standard Windows desktop displayed To verify that the oppy drive works, insert a known good oppy disk containing les into the drive, and then view the les on it by following these steps: a b c Double-click the My Computer/Computer icon on the desktop Double-click the Floppy Disk Drive (A:) icon in the window (see Figure 10-1) Observe the les and folders displayed Do you see les displayed _____________________

cPtr++ = 0;

This line assigns the pointer variable cPtr a value of 0 (making it point to location 0 in memory) and then increments it to 1 (making it point to location 1 in memory). This code will not compile. Here s a more likely scenario:

*cPtr++ = 0;